How do you split the charge to achieve the greatest force? Once split, the separation distance is fixed. Suppose you have a total charge q tot that you can split in any manner.(a) By what factor must you change the distance between two point charges to change the force between them by a factor of 10? (b) Explain how the distance can either increase or decrease by this factor and still cause a factor of 10 change in the force.Explicitly show how you follow the steps in the Problem-Solving Strategy for electrostatics. To illustrate this, calculate the acceleration of two isolated protons separated by 2.00 nm (a typical distance between gas atoms). Bare free charges do not remain stationary when close together.(a) What is the magnitude of the force on the test charge? (b) What is the direction of this force (away from or toward the +6 μC charge)? A test charge of +2 μC is placed halfway between a charge of +6 μC and another of +4 μC separated by 10 cm.If two equal charges each of 1 C each are separated in air by a distance of 1 km, what is the magnitude of the force acting between them? You will see that even at a distance as large as 1 km, the repulsive force is substantial because 1 C is a very significant amount of charge.How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them?.By what factor was their separation decreased? Two point charges are brought closer together, increasing the force between them by a factor of 25.What will the force become if the distance between them is increased by a factor of three? Two point charges exert a 5.00 N force on each other.(a) How strong is the attractive force between a glass rod with a 0.700 μC charge and a silk cloth with a –0.600 μC charge, which are 12.0 cm apart, using the approximation that they act like point charges? (b) Discuss how the answer to this problem might be affected if the charges are distributed over some area and do not act like point charges.What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of –30.0 nC?.Given the polar character of water molecules, explain how ions in the air form nucleation centers for rain droplets.Using Figure 3, explain, in terms of Coulomb’s law, why a polar molecule (such as in Figure 3) is attracted by both positive and negative charges.Given water’s polar character, explain what effect humidity has on removing excess charge from objects. Figure 3 shows the charge distribution in a water molecule, which is called a polar molecule because it has an inherent separation of charge.It is more easily affected by electrostatic forces than molecules with uniform charge distributions. The electrons spend more time near the oxygen than the hydrogens, giving a permanent charge separation as shown. Figure 3 shows a schematic representation of the outer electron cloud of a neutral water molecule. Use Figure 3 as a reference in the following questions. Schematic representation of the outer electron cloud of a neutral water molecule. The electrostatic force between two subatomic particles is far greater than the gravitational force between the same two particles.įigure 3.The Coulomb force is extraordinarily strong compared with the gravitational force, another basic force-but unlike gravitational force it can cancel, since it can be either attractive or repulsive. It is responsible for all electrostatic effects and underlies most macroscopic forces.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |